Three chocolates, four biscuits and five cakes cost
34. Six chocolates and eight biscuits cost 38.
Find the cost of each cake
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2
Step-by-step explanation:
let price of chocolate, biscuits and cake be x, y,z respectively
3x+4y+5z = 34.
2(3x+4y+5z) = 2×34
6x+8y+10z = 68 (equ. 1)
6x+8y = 38 (equ. 2)
subtracting equ. 2 from equ. 1 we get
6x + 8y + 10z - (6x+8y) = 68-38
6x-6x + 8y-8y + 10z = 30
10z = 30
z = 30/10
z = 3
z = cost of cake = 3
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Answer:
Step-by-step explanation:
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