Three circles A, B and C have a common centre O. A is the inner
circle, B is the middle circle and C is the outer circle. The radius of
the outer circle C, OP cuts the inner circle at X and the middle circle
at Y such that OX = XY = YP. Find the ratio of the area of the
region between the inner and middle circles to the area of the region
between the middle and outer circle.
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Chord AB of the outer circle cuts the inner circle at C and D. To prove: AC = BDConstruction: Draw OM = AB Proof : Since OM AB (by construction) OM
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The radius of the outer circle C, OP cuts the inner circle at X and middle circle at Y such that OX = XY = YP. The ratio of the area of the ...
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