three circles each of radius 3.5 CM are drawn in such a way that each of them touched the other two. find the area enclosed between these three circles
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Step-by-step explanation:
Join the centre of the circles with each other.
An equilateral triangle is formed with sides=7cm
Area of the region=
Area of∆-3×{area of sector}=
{√3/4×side×side}-{3×πr×r×@/360}=
{√3/4×7×7}-{3×22/7×3.5×3.5×60/360}=
192.65 sq. cm
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hope this helps u mate..............
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