Three circles of radii 4 5 and 8 touch each other externally find area
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area of circle divided by radius into 100
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AB = 4 cm = a
BC = 5 cm = b
and CA = 8 cm = c
Area of △ABC
= s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−√
s=AB+BC+CA2
=4+5+8/2=17/2=8.5
s - a = 8.5 - 4 = 4.5
s - b = 8.5 - 5 = 3.5
s - c = 8.5 - 8 = 0.5
√8.5*4.5*3.5*0.5−−
BC = 5 cm = b
and CA = 8 cm = c
Area of △ABC
= s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−√
s=AB+BC+CA2
=4+5+8/2=17/2=8.5
s - a = 8.5 - 4 = 4.5
s - b = 8.5 - 5 = 3.5
s - c = 8.5 - 8 = 0.5
√8.5*4.5*3.5*0.5−−
itigupta123:
= answer
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