Question

Three circles of radius 2 cm 3 cm and 4 centimetre touch each other externally find the perimeter of triangle formed by joining the centres of the circles

Answer 1

Answer:

Step-by-step explanation:

the perimeter = p

p =2* radius of circle 1+ 2*radius of circle 2+2*radius of circle 3

p =2*2+2*3+2*4

p = 10+8

p =18 cm

Answer 2

Answer:

18 cm

Step-by-step explanation:

It is given that three circles of radius 2 cm 3 cm and 4 centimeter touch each other externally.

We need to find the perimeter of triangle formed by joining the centers of the circles.

One side of the triangle = 2 + 3 = 5

Second side of the triangle = 3 + 4 = 7

Third side of the triangle = 2 + 4 = 6

The perimeter of the triangle is the sum of all sides.

$Perimeter=5+7+6$

$Perimeter=18$

Therefore, the perimeter of triangle formed by joining the centers of the circles.