Question

Three circles of radius 21 cm are placed in such a way that each circle touches the other two. What is the area of the portion enclosed by the three circles?

Answer 1

these three circles
= area of equilateral triangle - area of sectors
= Ar(ABC) - 3(area of sector)
= √3/4 r² - 3(∅/360)(πr²)

= (√3/4) - 3(60/360)(22/7)(3.5)²
= (√3/4) - (1/2)(22)(7/4)
= (√3/4) - (77/4)
= (√3 -77)/4 cm²