Three circles of radius 3.5 CM are drawn in such a way that each of them touches the other Two. find the area enclosed between these circles.
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Area which is enclosed in between these three circles
= area of equilateral triangle - area of sectors
= Ar(ABC) - 3(area of sector)
= √3/4 r² - 3(∅/360)(πr²)
= (√3/4) - 3(60/360)(22/7)(3.5)²
= (√3/4) - (1/2)(22)(7/4)
= (√3/4) - (77/4)
= (√3 -77)/4 cm2
= area of equilateral triangle - area of sectors
= Ar(ABC) - 3(area of sector)
= √3/4 r² - 3(∅/360)(πr²)
= (√3/4) - 3(60/360)(22/7)(3.5)²
= (√3/4) - (1/2)(22)(7/4)
= (√3/4) - (77/4)
= (√3 -77)/4 cm2
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