Math, asked by andersonjerin9303, 9 months ago

Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is

A) 1.967 B) 1.867 C) 1.767 D) 1.567

Answers

Answered by Anonymous
7

Answer: A) 1.967

Explanation:

required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with à = 60 degrees and r = 3.5cm)

(3√4*7*7)−(3*227*3.5*3.5*60360) sq cm

=(3√4*49)−(11*0.5*3.5) sq cm

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