Three circles with centers A,B and C touch each other externally. AB = 10cm, Bc = 8cm and AC = 6cm. Find the radius of the circle with center A.
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Step-by-step explanation:
Given: ABC is a triangle with AB = 10 cm, BC= 8 cm, AC = 6 cm. Three circles are drawn with centre A, B and C touch each other at P, Q and R respectively.
So, we need to find the radii of the three circles.
Let,
PA = AQ = x
QC = CR = y
RB = BP = z
So , we have
x + z = 10 ….. (i)
z + y = 8 …… (ii)
y + x = 6 ……. (iii)
Adding all the three equations, we have
2(x+y+z)=24
x + y + z = 24/2 = 12 ….. (iv)
Subtracting (i), (ii) and (iii) from (iv) we get
y = 12 – 10 = 2
x = 12 – 8 = 4
z = 12 – 6 = 6
Thus, radii of the three circles are 2 cm, 4 cm and 6 cm
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Answer:
Three circles are drawn touching each other with the vertices as their centres. Find the radii of the three circles. Solution Show Solution. Let the radii of ...
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