three circles with fixed Centre placed one besides other have diameter20% more than its left neighbor, if left most circle have 200 revolution, how many revolution will right most circle have
Answers
If the leftmost circle completes 200 revolutions, how many revolutions will the rightmost circle complete? ... one beside the other have diameters 20% more than that of it's "left neighbour". ... 11 1/2 ÷ 11 1/4is Diameter of a wire on a computer chip is 0.000003m and thickness of a piece of paper is 0.0016 cm .
Given : Three circles with fixed centres placed one beside the other have diameters 20% more than that of it’s “left neighbour”. If the leftmost circle completes 200 revolutions,
To find : how many revolutions will the rightmost circle complete?
Solution:
Let say Diameter of left most = D unit
Then Diameter of next = D + (20/100)D = 1.2D unit
Diameter of right most = 1.2D + (20/100)(1/2D) = 1.44 D unit
Circumference = π * Diameter
Circumference of Left most = πD unit
Circumference of next = π(1.2D) unit
Circumference of right most = π(1.44)D unit
1 revolution = Circumference
200 revolution of left most circle = 200 * (πD) unit
Distance covered = 200 * (πD) unit
Distance covered by right most = Revolutions * π(1.44)D
Revolutions * π(1.44)D = 200 * (πD)
=> Revolutions by right most = 200/1.44
=> Revolutions by right most = 138.9
approx 139 revolutions
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