Three co prime no. are in such that the product of first two no. is 667 and product of last two no. is 1073. find the sum of all three numbers?
Answers
Solution:
GIVEN,
Given numbers are co - prime numbers .
We know,
1 is common Factor for given numbers because of co - prime Numbers.
As per the question two products have the middle number in common.
Middle number = H.C.F of 667 and 1073 = 29.
Now we should find First number and Third number,
First number = 667 / 29
= 23.
Third number = 1073 / 29
= 37
∴ sum of all three numbers
= 23 + 29 + 37
= 89
pls follow me.
Given :
•3 numbers which are co-prime to each other such that the product of the 1st two numbers is 551 and that of the last 2 is 1073.
To find :
• The sum of 3 numbers?
Calculations :
★ Taking HCF (Higest common factor) for 551 and 1073.
= HCF = 29 ---(1)
★ Dividing the first number and last number by the 29, we get:
= 551/29
= 19 ---(2)
= 1073/29
= 37 ---(3)
★ As per the last case, sum of three numbers, we get:
= 29 + 19 + 37
= 85
★ Therefore, the sum of three numbers is equal to 85.