Question

Three coffees and two muffins cost a total of 7 dollars. Two coffees and four muffins cost a total of 8 dollars. What is the individual price for a single coffee and a single muffin

Answer 1

Answer:

THIS IS THE ANSWER

Step-by-step explanation:

LET COFFEE BE X

AND MUFFIN BE Y

3X+2Y=7                (1)

2X+4Y=8

X=8 - 4Y/2

ON SUBSTITUTING THIS IN (1)

3*(8-4Y/2) +2Y = 7

12-6Y+2Y = 7

-4Y = -5

Y=5/4

3X + 2*5/4 =7

3X+2.5=7  

X=7-2.5/3

X=1.5

Answer 2

Given:

• Cost of three coffees and two muffins = 7 dollars
• Cost of two coffees and four muffins = 8 dollars

To find:

• Individual price of single coffee and single muffin

Solution:

Let us take one coffee as x and one muffin as y,

According to Question,

$\fbox{3x + 2y = 7}$ - Eq. (i)

$\fbox{2x + 4y = 8}$ - Eq. (ii)

Multiply Eq. 1 by 2,

$→$ 2 (3x + 2y = 7)

$→\fbox{6x + 4y = 14}$ - Eq. (iii)

Subtract Eq. 2 from Eq. 3,

$→$ 6x + 4y = 14 - ( 2x + 4y = 8)

$→$ 6x + 4y = 14 - 2x - 4y = -8

$→$ 3x =6

$→$ $\text{x =} \frac{6}{3} = \frac{1}{2} =\text{1.5}$

Put the vales of x in Eq. 2,

$→$ 2×1.5 + 4y = 8

$→$ 3 + 4y = 8

$→$ 4y = 5

$→$ $\text{y} = \frac{5}{4} = \text{1.25}$

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Hence, Cost of one Coffee = 1.5 dollars

Cost of one Muffin = 1.25 dollars