three coin of same measure (1cm radius) are kept on a table in such a way that they touch each other. The area of the field formed by the coin in between is
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Answer:
Radius of each coin =1 cm
With all the three centres an equilateral triangle of side 2 cm is formed.
Area enclosed by coind = Area of equilateral triangle −3× Area of sector of angle 60
o
=
2
3
(2)
2
−3×
360
60
×π(1)
2
=
4
3
×4−3×
6
1
×π
=(
3
−
2
π
) cm
2
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