Question

Three coins are tossed 50 times. Find probability of
1.getting two heads
2.no heads
3.getting one head

Answer 1

Answer:

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When three coins are tossed together, the total number of outcomes =8

i.e., (HHH,HHT,HTH,THH,TTH,THT,HTT,TTT)

Solution (i):

Let E be the event of getting exactly two heads

Therefore, no. of favorable events, n(E)=3(i.e.,HHT,HTH,THH)

We know that, P(E) =

(Total no.of possible outcomes)/

(No.of favorable outcomes)

= 3/8

Solution (ii):

Let F be the event of getting atmost two heads

Therefore, no. of favorable events, n(E)=7(i.e.,HHT,HTH,TTT,THH,TTH,THT,HTT)

We know that, P(F) =

(Total no.of possible outcomes)/

(No.of favorable outcomes)

= 7/8

Solution (iii):

Let H be the event of getting at least one head and one tail

Therefore, no. of favorable events, n(H)=6(i.e.,HHT,HTH,THH,TTH,THT,HTT)

We know that, P(H) =

(Total no.of possible outcomes)/

(No.of favorable outcomes)

= 6/8

= 3/4

Solution (iv):

Let I be the event of getting no tails

Therefore, no. of favorable events, n(I)=1(i.e.,HHH)

We know that, P(H) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

= 1/8