three coins are tossed find the probebility of getting 2 tells
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I just learned in class that if you toss 3 coins (a quarter, a dime and a nickel), the probability of getting 2 tails only is 1414 and I don't really understand why.
My first intuition is that:
0 heads => 1 tail
1 head => 2 tails
2 heads => 1 tail
3 heads => 0 tails
Therefore, it should be 1414. I understand that the number of permutations is 8, thus:
HHH THT
HHT THH
HTT TTH
TTT HTH
And if you take those with 2 tails, it's 3838. But where is the flaw in my first reasoning? Why do I care about which coin gets Tails when I only want to know the probability of getting 2 tails?
My first intuition is that:
0 heads => 1 tail
1 head => 2 tails
2 heads => 1 tail
3 heads => 0 tails
Therefore, it should be 1414. I understand that the number of permutations is 8, thus:
HHH THT
HHT THH
HTT TTH
TTT HTH
And if you take those with 2 tails, it's 3838. But where is the flaw in my first reasoning? Why do I care about which coin gets Tails when I only want to know the probability of getting 2 tails?
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