Three coins are tossed once. Find the probability of: (a) 3 heads (b) exactly 2 heads (c) atleast 2 heads (d) atmost 2 heads (e) no tails (f) head and tail appear alternatively (g) atleast one head and one tail....
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When 3 unbaised coins are tossed, the total number of events = 8 They are {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT} (1) Number of favourable events (getting at least two heads) = 4 Probability of getting at least two heads = 4/8 = 1/2 (2) At most two heads That is no head or one head or 2 heads Probability of getting at most two heads = 7/8
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When 3 unbaised coins are tossed, the total number of events = 8 They are {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT} (1) Number of favourable events (getting at least two heads) = 4 Probability of getting at least two heads = 4/8 = 1/2 (2) At most two heads That is no head or one head or 2 heads Probability of getting at most two heads = 7/8
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