Question

Three coins are tossed once, find the probability of getting atleast one head.​

Answer 1

Answer:

Therefore, P(getting 1 head) = P(E3) = n(E3)/n(S) = 3/8. and, therefore, n(E4) = 7. Therefore, P(getting at least 1 head) = P(E4) = n(E4)/n(S) = 7/8.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Therefore, P(getting 1 head) = P(E3) = n(E3)/n(S) = 3/8. and, therefore, n(E4) = 7. Therefore, P(getting at least 1 head) = P(E4) = n(E4)/n(S) = 7/8.