Question

Three coins are tossed simultaneously 100 times with the following frequencies of different

outcomes:

Outcome

Frequency

No head

14

One head

38

Two heads

36

Three heads

12


What is the probability of getting (a) at least one head(b) more heads than tails (c) more tails than heads​

Answer 1

Answer:

Three coins are tossed simultaneously 100 times the following frequencies of different outcomes: Outcomes: No head One head Two heads Three head Frequency: 14 38 36 12 If the three coins are simultaneously tossed again, compute the probability of: (i) 2 heads coming up. (ii) 3 heads coming up.

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Answer 2

Answer:

Total number of outcomes = 100

Answer 1) : 2 heads coming up

Probability = 36/100

= 9/25

Answer 2) : 3 heads coming up

Probability = 12/100

= 3/25

Answer 3) : At least 1 head coming up

Probability = (36/100 + 38/100 + 12/100)

= 86/100

= 43/50

Answer 4) : Getting more heads than tails

Number of times 2 heads (2 heads and 1 tail) appears = 36

Number of times 3 heads (3 heads and 0 tail) appears = 12

Number of favorable outcomes = 36 + 12 = 48

Probability (Getting more heads than tails)

= Number of favorable outcomes/Total number of possible outcomes

= 48/100

= 12/25

Answer 5) : Getting more tails than heads

Number of times 2 tails (2 tails and 1 head) appears = 38

Number of times 3 tails (3 tails and 0 head) appears = 14

Number of favorable outcomes = 38 + 14 =52

Probability (Getting more tails than heads) = 52/100

= 13/25

Step-by-step explanation:

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