Three coins are tossed simultaneously 150 times with the following frequencies of different outcomes ( No of tails 0 1 2 3 ) (frequency 25 30 32 63) A at least 2 tails B exactly one tail
Answers
Answered by
37
Given, three coins are tossed simultaneously 150 times with the following frequencies of different outcomes.
No. of tails Frequency
0 25
1 30
2 32
3 63
a. P(exactly 1 tail) = 30/150 = 1/5
b. P(at least 2 tails) = P(2 tail) + P(3 tail)
= 32/150 + 63/150
= (32 + 63)/150
= 95/150
= 19/30
c. P(at most 3 tail) = P(0 tail) + P(1 tail) + P(2 tail) + P(3 tail)
= 25/150 + 30/150 + 32/150 + 63/150
= (25 + 30 + 32 + 63)/150
= 150/150
= 1
d. P(exactly 3 heads) = P(0 tail) = 25/150 = 1/6
No. of tails Frequency
0 25
1 30
2 32
3 63
a. P(exactly 1 tail) = 30/150 = 1/5
b. P(at least 2 tails) = P(2 tail) + P(3 tail)
= 32/150 + 63/150
= (32 + 63)/150
= 95/150
= 19/30
c. P(at most 3 tail) = P(0 tail) + P(1 tail) + P(2 tail) + P(3 tail)
= 25/150 + 30/150 + 32/150 + 63/150
= (25 + 30 + 32 + 63)/150
= 150/150
= 1
d. P(exactly 3 heads) = P(0 tail) = 25/150 = 1/6
Answered by
83
solution :-
Given, three coins are tossed simultaneously 150 times with the following frequencies of different outcomes.
No. of tails :- 0, 1 , 2, 3
Frequency:- 25, 30, 32, 63
a.) P(exactly 1 tail) = 30/150 = 1/5
b.) P(at least 2 tails) = P(2 tail) + P(3 tail)
= 32/150 + 63/150
= (32 + 63)/150
= 95/150
= 19/30
c. ) P(at most 3 tail) = P(0 tail) + P(1 tail) + P(2 tail) + P(3 tail)
= 25/150 + 30/150 + 32/150 + 63/150
= (25 + 30 + 32 + 63)/150
= 150/150
= 1
d. )P(exactly 3 heads) = P(0 tail) = 25/150 = 1/6
Given, three coins are tossed simultaneously 150 times with the following frequencies of different outcomes.
No. of tails :- 0, 1 , 2, 3
Frequency:- 25, 30, 32, 63
a.) P(exactly 1 tail) = 30/150 = 1/5
b.) P(at least 2 tails) = P(2 tail) + P(3 tail)
= 32/150 + 63/150
= (32 + 63)/150
= 95/150
= 19/30
c. ) P(at most 3 tail) = P(0 tail) + P(1 tail) + P(2 tail) + P(3 tail)
= 25/150 + 30/150 + 32/150 + 63/150
= (25 + 30 + 32 + 63)/150
= 150/150
= 1
d. )P(exactly 3 heads) = P(0 tail) = 25/150 = 1/6
Similar questions
Hindi,
8 months ago
Physics,
8 months ago
Computer Science,
8 months ago
Business Studies,
1 year ago
Social Sciences,
1 year ago
Science,
1 year ago