three coins are tossed simultaneously 200 times with the following frequencies of different outcomes . outcome 3 tails , 2 tail, 1 tail, no tail frequency, 20 , 68 , 82 , 30 respectively. if the three coins are tossed again simultaneously compute the probability of getting less than three tails.
Answers
Given:
Number of times the coins were tossed = 200
Frequency of getting 3 tails = 20
Frequency of getting 2 tails = 68
Frequency of getting 1 tail = 82
Frequency of getting no tail = 30
To find:
The probability of getting less than three tails when the three coins are tossed again.
Solution:
Probability of getting no tail = 30/200
Probability of getting 1 tail = 82/200
Probability of getting 2 tails = 68/200
The probability of getting less than 3 tails = probability of getting 0 tail + 1 tail + 2 tail
= 30/200 + 82/200+ 68/200
=180/200
=9/10
Therefore the probability of getting less than three tails is 9/10.
Answer:
0.9
Step-by-step explanation:
P(less than 3 tails)
= 68+82+30
200
= 180
200
= 9
10
= 0.9
Therefore, 0.9 is the probability of getting less than 3 tails.