Three coins are tossed simultaneously 350 times. The distribution of various outcomes is listed below:(i) Three tails:5 (ii) Two tails:95 (iii)One tail:120 (iv) No tails:80 Find the respective probability of each event and check that the sum of all probabilities is 1
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Hi friend ,
(i) P( three tails)= No. of times tail came up/ Total no. of toe coin is tossed.
P( three tails)= 5/350= 1/70
(ii) P (two tails) = 95/350
= 19/70
(iii) P( one tail) = 120/350
= 24/70
(iv) P(no tails)= 80/350
=16/70
Adding up all the probabilities:
1/70+19/70+24/70+16/70
60/70 is not equal to 1. So these outcomes are wrong.
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Hope this helped u..
PLZ MARK AS BRAINLIEST...
(i) P( three tails)= No. of times tail came up/ Total no. of toe coin is tossed.
P( three tails)= 5/350= 1/70
(ii) P (two tails) = 95/350
= 19/70
(iii) P( one tail) = 120/350
= 24/70
(iv) P(no tails)= 80/350
=16/70
Adding up all the probabilities:
1/70+19/70+24/70+16/70
60/70 is not equal to 1. So these outcomes are wrong.
----------------------------------------
Hope this helped u..
PLZ MARK AS BRAINLIEST...
neerajkumarvr:
Its really helping
Answered by
0
Answer:
Step-by-step explanation:
Total tosses=350
i. 5/35 0 = 1/70
ii. 95/35 0 = 19/70
iii. 120/35 0 = 24/70
iv. 80/350 = 16/70
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