Three coins are tossed simultaneously 500 times with the following frequency of different outcome. outcome =3tails 2tails 1tails no tails frequency =200 100 150 50 find the probability of getting 1=Atleast one tail 2=two head and one tail
Answers
Answered by
5
Answer:
Step-by-step explanation:
P(atleast one tail)=P (1 tail)+P (2 tail)+P (3 tail)
= 1-P(0 tail)
=1-(50÷500)
=1-(1/10)
=9/10
Answered by
15
Answer:
Step-by-step explanation:
3tail 2tails 1tail no tail
200 100 150 50
probabiity of atleast 1tail=
(150+100+200)/500
=450/500
=0.9
probability of two head and one tail= 150/500=15/50=0.3
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