Math, asked by prachitikadam591, 7 months ago


Three coins are tossed simultaneously.
Condition for event A : To get at least two heads.
Condition for event B : To get no head.
Condition for event C: To get head on the second coin.​

Answers

Answered by balasaisivakumar
19

Answer:

n(S)=2×2×2=8

n(A)=HHT,HTH,THH,HHH=4,

n(B)=TTT=1  

n(C)=THT,HHH,HHT,THH=4  

Q and R and P and Q are nutually exclusive as they have nothing in their intersection.

Answered by patilrutuja418
0

s = {HHH , HTH , HHT , HTT , TTT , TTH , THT , THH }

N (S) = 8

Event A = { HTH,HHT,HHH,THH }

N (A)= 4

Event B = {TTT}

N (B) = 1

Event C = {THT , HHH , HHT , THH }

N (C) =4

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