Question

three coins are tossed simultaneously find the event P is a event of getting at least 2 heads Q is the event of getting no head

Answer 1

if three coins are tossed simultaneously then
all possible events = TTT, THH, TTH, THT, HHH, HTT, HTH, HHT
no of all possible events = 8
probability of getting at least 2 heads = p
favourable events = THH, HHT, HHH, HTH
no of favourable events = 4
probability = no of fav. events / all possible events
= 4/8
(P) = 1/2
2nd case = getting no heads
fav. events = TTT
no of fav. events = 1
probability (Q) = 1/8
s