Question

three coins are tossed simultaneously.find the probability of getting atleast two heads?​

Answer 1

Total outcomes of 3 coins tossed simultaneously = 8 outcomes
Outcomes of getting atleast
2 heads = 3
Probability = no. Of outcomes / total no.
Of outcomes
P(E) = 3/8

Answer 2

Answer: 0.5

Step-by-step explanation:

Total number of possible outcomes = 2³ = 8.

The different possible outcomes are (sample space):

{TTT , TTH , THT , HTT , HHH , HHT , HTH , THH}

Th probability of getting atleast two heads also counts all three heads as one possibility.

So we have 4 favorable outcomes out of 8.

i.e : {HHT , HTH , THH , HHH}

Probability = No of favorable outcome ÷ Total No of outcomes

⇒ Probability = 4 ÷ 8 = 0.5

Hope this answer helps.