three coins are tossed simultaneously find the probability of getting atmost 3 heads
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Step-by-step explanation:
the probability of getting three heads is
Three coins are tossed simultaneously.
Possible outcomes = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}
Number of total outcomes = 8
(a) Let A be the event of getting three heeds
Thus, possible outcomes = {HHH} = 1
P(three heads) = 1 over 8
(b) Let B be the event of getting exactly two heeds
Thus, possible outcomes = {HHT, HTH, THH} = 3
P(exactly 2 heads) = 3 over 8
(c) Let A be the event of getting at least two heeds
Thus, possible outcomes = {HHH, HHT, HTH, THH} = 4
P(at least 2 heads) = 4 over 8 equals 1 half
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Three coins are tossed simultaneously. The probability of getting at most 3 heads is 1.
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