Three coins are tossed simultaneously. Find the probability of getting two heads.
FOR THE STUDENTS OF CLASS 10 ONLY
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1÷2
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Number of possible outcomes=8
{(H,H,H) (H,H,T),(H,T,H),(T,H,H),(H,T,T),(T,H,T),(T,T,H) & (T,T,T)}
Number of favourable outcomes (at least 2heads)=4
Probability (at least 2headd)= Number of favourable outcomes/total number of outcomes
Probability(P)(at least 2heads)= 4/8=½
P(at least 2 heads)= ½
Hence, the probability of getting at least 2 heads= ½.
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