Question

Three coins are tossed simultaneously. Find the probability of getting (a) head on first two coins (ii) exactly two heads (iii) tail on second coin
please explain the method to do this question​

Answer 1

Answer:

getting two heads

P(getting two heads) = P(E2)

     Number of times two heads appeared

=                 Total number of trials          

= 55/250

= 0.22

Answer 2

Answer:

Step-by-step explanation:

(i)2/8 =1/4=0.25

As only two times head can be on first two coins.

There would be 8 cases if 3 coins are tossed at a time.

So, total no of favourable outcomes/total no of outcomes

this formula is applicable to all the questions

(ii)0/8=0

(iii)4/8=1/2=0.5