Question

Three coins are tossed simultaneously find the probability of getting exactly two heads

Answer 1

Hi Mate !!

When three Coins are tossed then total outcomes are 8

( HHH )

( HHT )

( HTH )

( HTT )

( THH )

( THT )

( TTH )

( TTT )

Possible outcome :- 3

( HHT ) ( HTH ) ( THH )

E = Getting exact two heads

P ( E ) = Possible outcome/total outcomes

P ( E ) = 3/8

Answer 2

Three coins are tossed simultaneously.

Possible outcomes = [HHH, HHT, HTH, HTT, TTT, TTH, THT, THH]

No. of total outcomes = 8

Favourable outcomes = [HHT, HTH, THH]

No. of favourable outcomes = 3

Therefore,

$P(two \: heads) = \frac{ No. \: of \: favourable \: outcomes}{ No. \: of \: total \: outcomes}$

$= \frac{3}{8}$

Hence, the probability of getting exactly two heads is $\frac{3}{8}$.