Three coins are tossed simultaneously, find the
probability of getting at least 2 heads.
ans=1/2 if you know then solve!!
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Answer:
possible outcomes = (HHH, HHT, HTH, THH, HTT, THT, TTT)
let A be the event of getting at least 2 heads
thus, possible outcomes = (HHH, HHT, HTH ,THH) = 4
P (at least 2 heads) = 4/8 = 1/2
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