Question

Three coins are tossed simultaneously find the probability of getting (a) at least two heads (b) at most two heads

Answer 1

Answer:

(a) $\frac{4}{8}$

(b)  $\frac{7}{8}$

Step-by-step explanation:

Total outcomes when 3 coins are tossed simultaneously are -

HHH, TTT, THT, HTH, HHT, TTH, HTT, THH

Now,

(a) Here, the favorable cases are  - HHT, THH, HHH, HTH

because we have to find the cases where 2 or more heads are there. (i.e. atleast 2)

Required (P) = $\frac{favorable outcomes}{total number of outcomes}$

                    = $\frac{4}{8}$

                    = $\frac{1}{2}$

(B) Here, the favorable cases are -  TTT, THT, HTH, HHT, TTH, HTT, THH

because we have to find cases where 0, 1 or 2 heads are there. (i.e. utmost 2)

Required (P) = $\frac{favorable outcomes}{total number of outcomes}$

                    = $\frac{7}{8}$

Thanks,

Manav