three coins are tossed simultaneously.find the probability of getting exectly one head
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total outcomes n(s)=8
possible outcomes n(e)=4
(HTT,THT,TTH,TTT)
p(e)=n(e)/n(s)
p(e)=4/8
=1/2
greatplayerjohn:
of getting exactly one head
you included TTT in which there is no head at all
Answered by
0
Answer:
Step-by-step explanation:
favourable outcomes=
hhh,hht,hth,thh
ttt,tth,tht,htt.
number of outcome with one head=tth,tht,htt
therefore,probability=3/8
this implies, probability of getting exactly one head is
3/8
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