Question

three coins are tossed simultaneously.find the probability of getting exectly one head

Answer 1

total outcomes n(s)=8

possible outcomes n(e)=4

(HTT,THT,TTH,TTT)

p(e)=n(e)/n(s)

p(e)=4/8

=1/2

Answer 2

Answer:

Step-by-step explanation:

favourable outcomes=

hhh,hht,hth,thh

ttt,tth,tht,htt.

number of outcome with one head=tth,tht,htt

therefore,probability=3/8

this implies, probability of getting exactly one head is

3/8