three coins are tossed simultaneously find the probability of getting exactly one head
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Answered by
1
(T,TT)(TTH)(THT)(HTT)(HHT)(HTH)(THH)(HHH)=8
exactly one head=3
=3/8
Answered by
0
Answer:
Step-by-step explanation:
Total outcomes= TTH, TTT, HHT, HHH, HTH, THT, TTT, HHH
alleast one head
So
Favourable outcomes=6
Now
Probablity=6/8
=3/4
Hope it helps y!!!!(^_^)
poonam3863:
not at least case this is exactly one head
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