Three coins are tossed simultaneously. Find the probability of getting two heads.
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4
if three coins r toseed simultaneously.Let S be te sample space. Let h represents heads nd T represents tail.
S={ HHH, HTH, HTT, HHT ,TTT TTH, THT, THH}
n (S)= 8
Event A: getting two heads
A={HTH HHT THH}
n (A)=3
p (A)= n (A)/n (S)=8/3
the probability of getting 2 heads is 8/3
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Total number of outcomes = 8
Sample space = (HHH) (TTT) (HTT)
(TTH) (HTH) (THT)
(HHT) (THH)
P(of getting two heads ) = 3/8
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