Three coins are tossed simultaneously.
(i) S is the event of getting at least two heads.
(ii) A is the event if getting at least one tail.
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Answer: Total no. of outcomes-
n(T) = 8
1. S = at least 2 heads
n(S) = 4 outcomes i.e.{HHH, HTH, HHT, THH}
P(S) = 4/8 = 1/2
2. A = at least 1 tail
n(A) = 7 outcomes i.e. {HTH, HTT, HHT, TTT, THH, THT, TTH}
P(A) = 7/8
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