three coins are tossed simultaneously what is the probability of getting at least two heads
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{HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}. We see that {HHH, HHT, HTH, THH} have at least two heads. Therefore 4 out of 8 outcomes have at least two heads. P(at least 2 heads) = 4/8 = 1/2.
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