three coins are tossed simultaneously what is the probability of getting exactly two head
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yes , but ( hhh ) , ( ttt ) , ( htt ), ( tth ) ,( hth ), ( tht ) , etc
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GIVEN: Three coins are tossed simultaneously.
When three coins are tossed then the possible outcome will be:
TTT, THT, TTH, THH. HTT, HHT, HTH, HHH.
Total number of outcomes = 8.
(i) Let E1 = Event of getting exactly two heads
Then the outcome variable to E1 is THH, HHT ,HTH.
Number of outcomes favourable to E1 = 3
Probability (E1) = Number of favourable outcomes / Total number of outcomes
P(E1) = ⅜
Hence, probability of getting exactly two head ,P(E1) = ⅜ .
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