Question

Three coins are tossed together. Find the probability of getting
(i) exactly two tails
(ii) at least one head
(iii) at least one head and one tail

Answer 1

Step-by-step explanation:

Possible outcomes

HHH,HHT,HTH,THH,TTT TTH,THT,HTT

i) P(exactly two tails)=2/8=1/4

ii)P(at least one head)=7/8

iii)P(at least one head and one tail=6/8=3/4

Answer 2

Answer:i) 2/8= 1/4

ii) 3/8

iii)1/8

Step-by-step explanation:

(i) at least two heads are only two which are (THH, HHT)

so it becomes 2/8= 1/4

(ii) at most 1 head is only three (HTT, THT, TTH)

so it becomes 3/8

(iii) all head is only one that is (HHH)

so it becomes 1/8