Math, asked by sanjeevmalipatil13, 10 months ago

Three coins are tossed together find the probability of getting exactly 2 heads second one at most two heads third one at least one head and tail 4th no tail

Answers

Answered by harshit14088
1

Answer:

check solution

Step-by-step explanation:

tgere are 4total outcomes

probability of getting 2 heads is 1/4

probability of getting at most one head is 3/4

no tail = 1/4

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Answered by Anonymous
0

Step-by-step explanation:

Sample space = { (HHH), (HHT), (HTH), (THH), (TTT), (TTH), (THT), (HTT)}

Total outcome = 8

1. Exactly 2 head = { (HHT), (HTH), (THH)}

P ( exactly 2 head) = 3/8

2. At most 2 tails = { (HHT), (HTH), (THH), (TTH), (THT), (HTT)}

P (atmost 2 tails) = 6/8 => 3/4

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