Question

three coins are tossed together. find the probability of getting at least one tail​

Answer 1

Answer:

7/8

Step-by-step explanation:

Answer 2

ANS: Let ‘S’ be the sample – space. Then S = { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT }

(i) Let ‘E1’ = Event of getting all heads, Then E1 = { HHH }

|E1| = 1

P(E1) = |E1| / |S| = 1 / 8

(ii) Let E2 = Event of getting ‘2’ heads. Then:

E2 = { HHT, HTH, THH }

|E2| = 3

P (E2) = 3 / 8

(iii) Let E3 = Event of getting at least one head. Then:

E3 = { HHH, HHT, HTH, THH, HTT, THT, TTH }

|E3| = 7

P (E3) = 7 / 8

(iv) Let E4 = Event of getting at least one head, Then:

E4 = { HHH, HHT, HTH, THH, }

|E4| = 4

P (E4) = 4/8 = 1/2

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