Question

Three coins are tossed together. Find the probability of getting at least two heads and atmost two tails.​

Answer 1

*Solution:-

(i) getting at least two heads:-

Answer:

The probability of getting two heads and one tail on tossing three coins at once is equal to 3/8

Let's look into all the possible outcomes

of tossing three coins together.

Explanation:

We know that,

Probability of an event (E) = Number of favorable outcomes / Total number of outcomes

Let, H = Heads, T = Tails

Possible outcomes:

(H,H,H), (H,H,T), (H,T,H), (H,T,T), (T,H,H), (T,H,T), (T,T,H), (T,T,T)

Total number of outcomes = 8

Number of outcomes that gives two heads and one tail = 3

i.e, (H,H,T), (H,T,H), (T,H,H)

Thus, number of favorable outcomes = 3

Probability of getting two heads and one tail = Number of favorable outcomes / Total number of outcomes

• = 3/8

Thus, the probability of getting two

heads and one tail on tossing three coins at once is equal to 3/8.

*(ii) Getting atmost two tails

Answer:

Let D be the event of getting atmost two tails.

• D = {HTT, TTT, TTH, THT, THH, HHT, HTH}
• n(D) = 7
• P(D) = n(D)/n(S) =7/8.

Hope it helps you a lot.

#Be Brainly.

Answer 2

Answer:

1) 3/8

2) 7/8

Step-by-step explanation:

mark me as brainliest