Question

three coins are tossed together. write all the possible outcomes and find the probability of getting exactly two heads ​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The probability of getting exactly two heads is 3/8

Solution:

Given that,

Three coins are tossed together

The possible outcomes are:

(HHH) , (HHT) , (HTH) , (THH) , (HTT) , (THT) , (TTH) , (TTT)

Number of possible outcomes = 8

Favorable outcomes = exactly two heads ​ = (HHT) , (HTH) , (THH)

Number of Favorable outcomes =  3

Find the probability of getting exactly two heads ​

$Probability = \frac{ \text{ Number of Favorable outcomes }}{ \text{ Number of possible outcomes }} \\\\Probability = \frac{ 3 } { 8 }$

Thus the Probability is found

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A die is thrown, Find the probability of getting:

(a)a prime number

(b)2 or 4

(c)a multiple of 2 or 3

(d)an even prime number

(e)a number greater than 5

(f)a number lying between 2 and 6

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