Question

Three coins are tossed up in the air, one at a time. What is the probability that two of them will land heads up and one will land tails up?

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

For the given question, let us first write the required sample space:-

H  H

H  T

T  H

T   T

So, these were the sample spaces. Let's read the question carefully now.

What is the probability that two of them will land heads up and one will land tails up?

Certainly, 2 questions are mixed and matched. So, if two will land Heads up, it has only one case - So, 1/4 is the answer.

One will land heads up means other will be tail, so, here we have 2 cases. So, the answer is 2/4 or we can simplify it to write it as 1/2.

Hence, the required answers.

Answer 2

Answer:

Let H be the heads and T be the tails.

Sample Space(S)={HHH,HTH,THH,TTH,HHT,HTT,THT,TTT}

n(S)=8

Let A be the set of getting at most 2 tails.(two or less than two tails)

Therefore,

A={HHH,HTH,THH,TTH,HHT,HTT,THT}

n(A)=7

Since,

P(A)=n(A)/n(S)

P(A)=7/8

Therefore, the probability of getting at most 2 tails is 7/8.

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