Question

three coins are tossee together, the the probability of getting at most one head is​

Answer 1

Answer:

E³= {HTT, THT, TTH} and, therefore, n(E³) = 3. Therefore, P(getting 1 head) = P(E³) = n(E³)/n(S) = 3/8.

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Answer 2

Answer:

HI Bro I have you answer

Step-by-step explanation:

E3 = {HTT, THT, TTH} and, therefore, n(E3) = 3. Therefore, P(getting 1 head) = P(E3) = n(E3)/n(S) = 3/8