Question

three coins tossed simultaneously find the probability of getting at most two heads​

Answer 1

Answer:

let the event be getting atmost two heads

no: of possible outcomes = 7

total no: of favourable outcomes = 8

P(E) = no: of possible outcomes / total no: of favourable outcomes

7/8

therefore probability of getting atmost two heads = 7/8

total no: of favourable outcomes

TTT. HHH. THT. HTH. TTH. HHT. THH. HTT

I think this is the answer.............I hope it helps you