three collinear horizontal forces of magnitude 150n, 450n and 300n are acting on a rigid body. determine the resultant of forces when (i) all the forces are acting in the same direction; (ii) the force of 300N act in the same direction
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Answer:
Given :
Three col linear horizontal forces of magnitude 150 N, 450 N and 300 N are acting on a rigid body . '
To Find :
The resultant of forces when all the forces are acting in the same direction .
Solution :
We know , force is a vector quantity .
Also , when vectors are added in same direction the net magnitude is the sum of all vector magnitude .
So , F_{max}=F_1+F_2+F_3F
max
=F
1
+F
2
+F
3
Putting value of F_1 , F_2 \ and\ F_3F
1
,F
2
and F
3
in above equation .
We get :
\begin{gathered}F_{max}=F_1+F_2+F_3\\\\F_{max}=150+450+300\ N\\\\F_{max}=900\ N\end{gathered}
F
max
=F
1
+F
2
+F
3
F
max
=150+450+300 N
F
max
=900 N
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