Question

Three collinear horizontal forces of magnitude 150n, 450n and 300n are acting on a rigid body. Determine the resultant of forces when (i) all the forces are acting in the same direction; (ii) the force of 300n act in the same direction.

Answer 1

I) if all the forces act along the same direction then resultant force

N =n1+n2+n3

=150+450+300=900N

ii)

Answer 2

Given :

Three col linear horizontal forces of magnitude 150 N, 450 N and 300 N are acting on a rigid body . '

To Find :

The resultant of forces when all the forces are acting in the same direction .

Solution :

We know , force is a vector quantity .

Also , when vectors are added in same direction the net magnitude is the sum of all vector magnitude .

So , $F_{max}=F_1+F_2+F_3$

Putting value of $F_1 , F_2 \ and\ F_3$ in above equation .

We get :

$F_{max}=F_1+F_2+F_3\\\\F_{max}=150+450+300\ N\\\\F_{max}=900\ N$

Therefore , this is the required solution .

Learn More :

Vectors

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