Three concentric conducting shell A, B and C are given. B shell is earthed. Show charge distribution on surface of each shell.
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Explanation:
As charge inside shell is zero so charge distribution will be as shown in figure below. Thus charge induced at surface 1 is q
1
=−q
As shell B is earthed so potential at any point (P) on this shell will be zero.i,e
V
P
=0=V
A,out
+V
B,surface
+V
C,in
Lets assume charge on B's surface q
2
is x
or 0=k
2R
q
+k
2R
(−q+x)
+k
3R
2q
or 0=k
2R
x
+k
3R
2q
x=−
3
4
q
Thus, q
2
=x=−
3
4
q,q
3
=−x=
3
4
q and q
4
=2q+x=2q−
3
4
q=
3
2
q
solution
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