Question

Three condensers of capacitances 10,20,30 micro farad connected in series and then connected in parallel .the ratio of tje result of the resultant capacitances in the two cas3s is

Answer 1

series:

1/c = 1/c1+1/c2+1/c3

=1/10+1/20+1/30

=6+3+2/60

=11/60

capacitance in series= 60/11micro farads.

parallel:

c=c1+c2+c3

=10+20+30

=60 micro farads.