Question

three consective integers are such that when they are taken in increasing order and multiplied by 2,3 snd 4 respectively, they add up to 74.Find these numbers?​

Answer 1

Step-by-step explanation:

Let first integer be x

Second integer = x + 1

3rd integer = (x + 1) + 1

= x + 2

Now,

Multiply 1st number by 2 = 2x

Multiply 2nd number by 3 = 3(x + 1)

Multiply 3rd number by 4 = 4(x + 2)

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Given, sum of these three is 74

2x + 3(x + 1) + 4(x + 2) = 74

2x + 3x + 3+ 4x + 8 = 74

2x + 3x + 4x +3+8=74

9x + 11 = 74

9x = 74-11

9x = 63

x = 63 / 9

X = 7

First integer = x= 7

Second integer = x + 1 = 7+1=8

Third integer = x + 2 = 7+2=9

( Integers are -2, -1, 0, 1, 2, ...

Consecutive integers are 1, 2, 3

Difference between Consecutive

Integers = 1

If number starting from 1, then

First number = 1

Second number = 1 + 1 = 2

Third number = 2 + 1 = 3)

Answer 2

Answer:

7,8,9

Step-by-step explanation:

Let the three consective numbers be n,n+1,n+2 respectively

According to the problem:

2n+3(n+1)+4(n+2)=74

Or 9n+11=74

9n=63

n=7

so, the numbers are 7,8,and 9